Skip to article frontmatterSkip to article content
Site not loading correctly?

This may be due to an incorrect BASE_URL configuration. See the MyST Documentation for reference.

Problem set — thermodynamic potentials

Problem set: thermodynamic potentials

Exam-style problems. Work them with a pen before touching a computer; problems 4 and 5 are meant to be finished in the laboratory, and problem 6 is a challenge. Solutions and marking rubrics live with the instructor material and are deliberately not on this site.

Take kB=1.381×10−23 J K−1\kB = 1.381 \times 10^{-23}\ \mathrm{J\,K^{-1}} and R=8.314 J mol−1 K−1R = 8.314\ \mathrm{J\,mol^{-1}\,K^{-1}} throughout.

Problem 1 — the Gibbs Maxwell relation on an ideal gas

(a) Starting from dG=−S dT+V dP\mathrm{d}G = -S\,\mathrm{d}T + V\,\mathrm{d}P at fixed NN, derive the Maxwell relation

(∂S∂P)T=−(∂V∂T)P.\left(\frac{\partial S}{\partial P}\right)_T = -\left(\frac{\partial V}{\partial T}\right)_P .

(b) Use it to show that for an ideal gas

(∂S∂P)T=−NkBP,\left(\frac{\partial S}{\partial P}\right)_T = -\frac{N \kB}{P} ,

and hence find the entropy change of one mole of an ideal gas compressed isothermally from 1 to 10 bar10\ \mathrm{bar}.

(c) Check your answer to (b) against the volume form of the entropy change, using (∂S/∂V)T=(∂P/∂T)V(\partial S/\partial V)_T = (\partial P/\partial T)_V instead.

(d) Explain in words why squeezing a gas at fixed temperature lowers its entropy, and where the entropy goes.

Problem 2 — the potentials and the Euler relation

(a) Using the Euler relation U=TS−PV+μNU = TS - PV + \mu N, show that G=μNG = \mu N, and find the corresponding expressions for FF and HH.

(b) Starting from F=U−TSF = U - TS and module 09’s differential form of the fundamental relation, derive dF=−S dT−P dV+μ dN\mathrm{d}F = -S\,\mathrm{d}T - P\,\mathrm{d}V + \mu\,\mathrm{d}N.

(c) For one mole of argon at 300 K300\ \mathrm{K} and 1 bar1\ \mathrm{bar} the Sackur–Tetrode entropy is S=155.0 J K−1S = 155.0\ \mathrm{J\,K^{-1}}. Compute UU, HH, FF and GG. Module 09 found that for this gas μN=−T (S−52NkB)\mu N = -T\,(S - \tfrac{5}{2} N \kB); check that your GG agrees with it.

(d) A student writes the ideal gas’s energy as U(T,V)=32NkBTU(T, V) = \tfrac{3}{2} N \kB T and differentiates with respect to VV to find the pressure. What do they get, and what has gone wrong?

Problem 3 — splitting water: heat versus enthalpy

At 298 K298\ \mathrm{K} and 1 bar1\ \mathrm{bar}, splitting one mole of liquid water into hydrogen and oxygen gas has ΔH=285.8 kJ\Delta H = 285.8\ \mathrm{kJ} and ΔG=237.1 kJ\Delta G = 237.1\ \mathrm{kJ}.

(a) Show that at fixed TT and PP the electrical work done on the cell is at least ΔG\Delta G.

(b) Find the smallest voltage that can split water, given that two electrons pass per molecule and the Faraday constant is 96 485 C mol−196\,485\ \mathrm{C\,mol^{-1}}.

(c) A cell runs at 1.80 V1.80\ \mathrm{V}. Per mole of water split, find the electrical work, the heat that crosses the boundary, and its direction.

(d) Explain why “ΔH\Delta H is the heat of the reaction” is true for the same reaction run by burning hydrogen in reverse at constant pressure, and false for the cell.

Problem 4 — the Einstein solid’s free energy, numerically

The Einstein solid of module 09 has, per oscillator,

U=εeε/kBT−1,S=kB[(1+x)ln⁡(1+x)−xln⁡x],x=Uε.U = \frac{\varepsilon}{e^{\varepsilon / \kB T} - 1} , \qquad S = \kB \Big[ (1 + x) \ln (1 + x) - x \ln x \Big] , \qquad x = \frac{U}{\varepsilon} .

(a) Show algebraically that F=U−TSF = U - TS equals kBTln⁡(1−e−ε/kBT)\kB T \ln\left(1 - e^{-\varepsilon/\kB T}\right) per oscillator.

(b) In the laboratory, tabulate U(S)U(S) on a grid of NN points and Legendre-transform it numerically. Plot the largest error of the result against NN, measured two ways: at the temperature each point should have, and on the curve F(T)F(T). Report both observed orders.

(c) Explain why the two orders differ, using the fact that f−p xf - p\,x is stationary in xx at the true tangent point.

(d) Why does the transform need U(S)U(S) to be convex, and which property of the solid from module 09 guarantees it?

Problem 5 — entropy from a pressure gauge: ideal versus real

(a) Show that for the van der Waals gas

(∂P∂T)V=NkBV−Nb,\left(\frac{\partial P}{\partial T}\right)_V = \frac{N \kB}{V - N b} ,

and integrate the Maxwell relation from FF to find the entropy change on an isothermal expansion from V1V_1 to V2V_2.

(b) For one mole of carbon dioxide (b=4.27×10−5 m3 mol−1b = 4.27 \times 10^{-5}\ \mathrm{m^3\,mol^{-1}}) expanding from 0.20 to 0.60 L0.60\ \mathrm{L} at fixed temperature, compute the entropy change, and compare it with the ideal-gas value.

(c) In the laboratory, simulate gauge readings with 0.5%0.5\% noise at five temperatures and a grid of volumes, and reconstruct ΔS\Delta S with its error bar. How many volumes do you need before the error from the integration rule is smaller than the error from the noise?

(d) Explain why the attraction constant aa plays no part in the answer.

Problem 6 — challenge: an ideal chain and the rubber band

Model a polymer as a chain of nn links of length ℓ\ell, each pointing either left or right along a line, with no energy cost for either direction. With n+n_+ links pointing right, the chain’s end-to-end length is L=(2n+−n) ℓL = (2 n_+ - n)\,\ell.

(a) Show that the number of arrangements with length LL is the binomial coefficient (nn+)\binom{n}{n_+}, and that for ∣L∣≪nℓ|L| \ll n\ell the entropy is approximately

S(L)=S(0)−kBL22nℓ2.S(L) = S(0) - \frac{\kB L^2}{2 n \ell^2} .

(b) The chain’s energy does not depend on LL. Using dF=−S dT+f dL\mathrm{d}F = -S\,\mathrm{d}T + f\,\mathrm{d}L, show that the tension needed to hold it at length LL is

f=−T(∂S∂L)T=kBTLnℓ2.f = -T\left(\frac{\partial S}{\partial L}\right)_T = \frac{\kB T L}{n \ell^2} .

(c) Predict what a chain holding a fixed weight does when heated, and what happens to its temperature when it is stretched quickly.

(d) The laboratory’s rubber band gives (∂f/∂T)L=5.79±0.17 mN K−1(\partial f/\partial T)_L = 5.79 \pm 0.17\ \mathrm{mN\,K^{-1}} at a tension of 2.00 N2.00\ \mathrm{N} and 295 K295\ \mathrm{K}. The ideal chain predicts a tension exactly proportional to TT. How far does the band depart from that, and what does the departure measure?